(6)/(n^3-3n^2)=(5)/(3n)-(n-6)/(n^3-3n^2)

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Solution for (6)/(n^3-3n^2)=(5)/(3n)-(n-6)/(n^3-3n^2) equation:


D( n )

3*n = 0

n^3-(3*n^2) = 0

3*n = 0

3*n = 0

3*n = 0 // : 3

n = 0

n^3-(3*n^2) = 0

n^3-(3*n^2) = 0

n^3-3*n^2 = 0

n^3-3*n^2 = 0

n^2*(n-3) = 0

n-3 = 0 // + 3

n = 3

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:3) U (3:+oo)

6/(n^3-(3*n^2)) = 5/(3*n)-((n-6)/(n^3-(3*n^2))) // - 5/(3*n)-((n-6)/(n^3-(3*n^2)))

6/(n^3-(3*n^2))+(n-6)/(n^3-(3*n^2))-(5/(3*n)) = 0

6/(n^3-3*n^2)+(n-6)/(n^3-3*n^2)+(-5/3)*n^-1 = 0

6/(n^3-3*n^2)+(n-6)/(n^3-3*n^2)-5/(3*n) = 0

n^3-3*n^2 = 0

n^3-3*n^2 = 0

n^2*(n-3) = 0

n-3 = 0 // + 3

n = 3

n^2*(n-3) = 0

6/(n^2*(n-3))+(n-6)/(n^2*(n-3))-5/(3*n) = 0

(3*6*n)/(3*n*n^2*(n-3))+(3*n*(n-6))/(3*n*n^2*(n-3))+(-5*n^2*(n-3))/(3*n*n^2*(n-3)) = 0

3*n*(n-6)-5*n^2*(n-3)+3*6*n = 0

3*n^2-5*n^3+15*n^2 = 0

18*n^2-5*n^3 = 0

18*n^2-5*n^3 = 0

n^2*(18-5*n) = 0

18-5*n = 0 // - 18

-5*n = -18 // : -5

n = -18/(-5)

n = 18/5

n^2*(n-18/5) = 0

(n^2*(n-18/5))/(3*n*n^2*(n-3)) = 0

(n^2*(n-18/5))/(3*n*n^2*(n-3)) = 0 // * 3*n*n^2*(n-3)

n^2*(n-18/5) = 0

( n-18/5 )

n-18/5 = 0 // + 18/5

n = 18/5

( n^2 )

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in { 0}

n = 18/5

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